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-13x^2+1430x-23400=0
a = -13; b = 1430; c = -23400;
Δ = b2-4ac
Δ = 14302-4·(-13)·(-23400)
Δ = 828100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{828100}=910$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1430)-910}{2*-13}=\frac{-2340}{-26} =+90 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1430)+910}{2*-13}=\frac{-520}{-26} =+20 $
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